4(2m^2+5-3)=0

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Solution for 4(2m^2+5-3)=0 equation: 



4(2m^2+5-3)=0

We multiply parentheses

8m^2+20-12=0

We add all the numbers together, and all the variables

8m^2+8=0

a = 8; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·8·8
Δ = -256
Delta is less than zero, so there is no solution for the equation

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